Slingshooting against the necessity of identity
The set is the empty
set if p is false, otherwise it is the set of all numbers. Hence
iff either p and q are both false or p and q are both true. So
1)![]()
Moreover, (1) isn't contingent. It doesn't just happen to be the
case at our world that iff p and q have the same truth
value. Such truths of logic and set theory hold with necessity:
2)![]()
Now assume the necessity of identity:
3)![]()
From (1) and (3) it follows that
4)![]()
And from (2) and (4) it follows that
5)![]()
But (5) is absurd. (In fact, (5), together with the innocent assumption that there is any necessary truth, entails that all truths are necessary truths: let p be the necessary truth and q any other truth.)
So what's wrong?
(2) is true (in the right-to-left direction) only if "{x:x in N & p}" etc are construed as non-rigid designators--i.e., as picking out, wrt a world w, the set of all x such that in w: (x is in N and p), rather than the set of all x such that in the actual world: (x is in N and p).
The rest of the derivation fails if they are so construed.
If we construe "{x:x in N & p}" in the way described, then from 1 and 3 it only follows that:
(4*) (p < - > q) -> (w)(z)(w={x:x in N & p} & z={x:x in N & q} -> NEC:(w=z))
and from 2 and 4*, 5 does not follow.